Solve: 23a + 6 > 0
a>9A is greater than 9
a β9A is greater than negative 9
<...
![Mathematics](/tpl/images/cats/mat.png)
Mathematics, 12.10.2020 22:01, rboehm59
Solve: 23a + 6 > 0
a>9A is greater than 9
a β9A is greater than negative 9
a<β9
![answer](/tpl/images/cats/otvet.png)
Answers: 1
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