The width of a rectangle is four feet more than six times its length, L. If the perimeter of the rectangle is 568 feet, what is the length of the rectangle?

Hi there!

Your answer is:

The length is 40

Step-by-step explanation:

W=4+6L

P=568

Perimeter formula

W+W+L+L=568

Plug in known values!

(4+6L)+(4+6L) + L +L = 568

Solve for L

14L + 8 = 568

-8

14L = 560

/14

L=40

this story was prepared by jim

mccullaugh in los angeles and

al stewart in new york.

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(continued on page 79)

step-by-step explanation: