The marketing department of a company has a budget of $30,000 for advertising. A television ad costs $1000a radio ad costs $200 and a newspaper ad costs $500. The department wants to run 50 ads per month and have as many radio ads as television and newspaper ads combined. How many of each type of ad should the department run each month

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

i have no

a: kite

step-by-step explanation:

figure lmno is located at l (1, 2) m (3, 2), n (3, 0), and o (0, −1). use coordinate geometry to best classify quadrilateral lmno.