A local zoo has two large snakes. The anaconda is currently 5.23 meters long and grows 1.27 meters every month. The python is 4.76 meters long and grows 2.04 meters per month. How many months (m) does the zookeeper need to wait for the two snakes to be the same length?

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Step-by-step explanation:

Given that:

Anaconda:

Current length = 5.23metres

Growth rate = 1.27 metres per month

Python :

Current length = 4.76metres

Growth rate = 2.04metres per month

Number of months (m) in which both will be of the same length:

Anaconda = python

5.23 + 1.27m = 4.76 + 2.04m

Solve for m

5.23 - 4.76 = 2.04m - 1.27m

0.47 = 0.77m

0.47 / 0.77 = 0.77m / 0.77

0.610 = m

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: