Merry is making an abstract triangular collage for the wall. She has 14 feet of edging to go around the collage. If the longest side is twice the smallest and the other side is four less than three times the smallest, find the length of each side of the triangular collage

The length of each side of the triangular collage:

a = smallest side = 3 feet

b = other side(second side) = 5 feet

c = Longest side = 6 feet

Step-by-step explanation:

She has 14 feet of edging to go around the collage.

14 feet = Perimeter of the triangle

The Perimeter of a Triangle = a + b + c where

a = smallest side

b = other side(second side)

c = Longest side

From the question, we are told that:

If the longest side is twice the smallest

c = 2a

The other side is four less than three times the smallest,

The other side = b

b = 3 × a - 4

b = 3a - 4

Hence,

P = a + b + c

14 = a + 3a - 4 + 2a

14 = a + 3a + 2a -4

14 = 6a - 4

Collect like terms

14 + 4 = 6a

18 = 6a

a = 18/6

a = 3ft

Therefore the smallest side = 3

The Longest side(c) = 2a

c = 2 × 3

c = 6ft

The other side(b) = 3a - 4

= 3(3) - 4

= 9 - 4

= 5 feet.

Therefore, the length of each side of the triangular collage:

a = smallest side = 3 feet

b = other side(second side) = 5 feet

c = Longest side = 6 feet

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75