Two cars travel at the same distance. The first car travel at 50 miles per hour and reaches its destination at t hours. The second car travels at a rate of 60 miles per hour and reaches its destination 1 hour earlier than the first car how long does it take for the first car to reach its destination

It would take the first car 6 hours to reach its destination.

Speed is the ratio of distance to time. It is given by:

Speed = distance /time

Since the two cars travel at the same distance, let d represent this distance.

The first car travel at 50 miles per hour and reaches its destination at t hours. Hence:

50 = d / t

d = 50t   (1)

The second car travels at a rate of 60 miles per hour and reaches its destination 1 hour earlier than the first car. Hence the time = t - 1. Hence:

60 = d / (t - 1)

d = 60(t - 1)

d = 60t - 60   (2)

Equating both equations gives:

50t = 60t - 60

10t = 60

t = 6 hours

Hence it would take the first car 6 hours to reach its destination

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The first car reaches its destination in 6 hours.

Step-by-step explanation:

Speed of the first car = 50 miles per hour

Time taken = t hours

Distance travelled = Speed × Time = 50 t

Speed of the second car = 60 miles per hour

Time taken = hours

Distance travelled = Speed × Time =

As two cars travel the same distance,

So, the first car reaches its destination in 6 hours.

b is the answer that makes most sense

step-by-step explanation:

answer: city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

since we have given that

total annual rainfall a city record = 40 inches

this year, total rainfall recorded = 37.6 inches

number of inches of rainfall   is needed to match the record of 40 inches is given by

hence, city needs 2.4 inches of rainfall more to match the record of 40 inches.