Jada earned $50 babysitting and plans to use the money to go to the fair l. admission to the fair is $5 and each ride is $2.50.while at the fair she buys a funnel cake for $3.what is the maximum number of rides jada can ride?

The maximum number of rides is 16

Step-by-step explanation:

She has a total of $50 and spends $3 for the cake and $5 for admission. She has to spend $2.50 for every ride.

Your equation would be set up as:

$50=$5+$3+$2.50x

You would combine like terms and get

$50=$8+$2.50x

Subtract the $8 from $50 and you get

$42=$2.50x

Divide each number by 2.50 and you get

16.8=x, you cannot have a decimal as an answer since she cannot ride eight tenths of a ride so the maximum number of rides is 16

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

the answer is c hope it

step-by-step explanation: