Question 13(Multiple Choice Worth 1 points) (8.03 LC) A set of equations is given below: Equation C: y = 7x + 12 Equation D: y = 7x + 2 How many solutions are there to the given set of equations? One solution Two solutions Infinitely many solutions No solution

No solutions

Step-by-step explanation:

y=7x+12;y=7x+2

Step: Solvey=7x+12for y:

y=7x+12

Step: Substitute7x+12foryiny=7x+2:

y=7x+2

7x+12=7x+2

7x+12+−7x=7x+2+−7x(Add -7x to both sides)

12=2

12+−12=2+−12(Add -12 to both sides)

0=−10

you already gave the answer

step-by-step explanation:

x^2 + 81

we can factor this using difference of square binomials.

rewrite the equation:

x^2 - (-81)

factor:

(a^2 - b^2) = (√a^2 + √b^2)(√a^2 - √b^2)

(x^2 - (-81) = (x + √-81)(x - √-81)

we can remove the - from under the radical by multiplying it by i.

(x^2 - (-81) = (x + i√81)(x - i√81)

(x^2 - (-81) = (x + 9i)(x - 9i)

we can check our answer by using foil:

x^2 - 9ix + 9ix - 81i^2

x^2 - 81^2

i^2 = -1

x^2 + 81