The equation
(k + 3) x^2+ 6x + k = 5, where k is a constant,
has two distinct real solutions...
Mathematics, 11.10.2020 08:01, Vanesssajohn2962
The equation
(k + 3) x^2+ 6x + k = 5, where k is a constant,
has two distinct real solutions for x.
Show that k satisfies
k^2– 2k – 24 < 0
Answers: 3
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