1) Knowing that in a PA the 1st term is 6 (a1 = 6) and the ratio is 5 (r = 5), write the first 5 terms of the PA Resp PA = (, , , , )

2) Fill in the parentheses with 1 for Ascending AP, 2 for Descending AP and 3 for Constant AP. Also enter the ratio value

() (5,5,5,5 ) r =
() (-7, -3, 1, 5, ...) r =
() (8, 4, 0, -4, ) r =

3) Determine the 5th term (a5) and the 6th term (a6) of the BP (3,7,11,15, ...)
** use the method that is safe for you.

Resp. a5 = e. a10 =

4) Defines the 3rd term (a3) of the PA (x-2, x-1, ...).
Resp. r = e. a3 =

The general term of AP is an = a1 + (n-1) .r

5) Using the formula above, knowing that r = 2 and a10 = 23, I discover the value of the 1st term (a1). Resp. a1 =

6) Using the formula above, knowing that a1 = 3 and r = 7, find the value of the 10th term (a10). Resp. a10 =

7) using the formula above, knowing that a1 = 2 and a11 = 32, find out the reason.
Resp. r =