Which of the equations have no real solution? Why do you say so?

With rational equations we must first note the domain, which is all real numbers except m=−3 and m=3. That is, these are the values of m that will cause the equation to be undefined. Since the least common denominator of m+3, m−3, and m2−9 is (m+3)(m−3), we can mulitply each term by the LCD to cancel out the denominators and reduce the equation to (m−3)+(m+3)=6. Combining like terms, we end up with 2m=6. Dividing both sides of the equation by the constant, we obtain an answer of m=3. However, this solution is NOT in the domain. Thus, there is NO SOLUTION because m=3 is an extraneous answer.

0

step-by-step explanation:

you can not divide by 0 so 4 ÷ 0 would be 0

0 × 9999 =0

mark brainliest   : )

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,