Rebecca wants to bye cupcakes and juice boxes for a party. Cupcakes come in packages of 12, and juice boxes come in packages of 10. She wants an equal number off cupcakes and juice boxes. What is the fewest number of packages of each Rebecca should buy?

Rebecca would need to buy 5 packages of cupcakes and 6 packages of juice boxes

Step-by-step explanation:

To find the equal number of cupcakes and juice boxes, you have to find the LCM(least common multiple)

12×1 = 12 ≠ 10 ×1 = 12

12×2 = 24 ≠ 10×2 = 20

12×3 = 36 ≠ 10×3 = 30

12×4 = 48 ≠ 10×4 = 40

12× 5 = 60 ≠ 10×5 = 50

12 × 5 = 60 = 10×6 = 60

Therefore, Rebecca would need to buy 5 packages of cupcakes and 6 packages of juice boxes

Hope this made sense!!!

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

do you have the measurements?