When you solve the slope intercept of x + 2y = 16, and get the slope of -0.5, where does the -x come from when switching from standard to y = mx + b form? I attempted doing the problem using this:
x + 2y = 16 ---> 2y = x + 16

But apparently the correct equation to use is:
2y = -x + 16

So where does -x come from if the x is positive?

Consider the integral: 4 0 16 − y2 − 16 − y2 4 1 x2 + y2 dz dx dy . (a) describe w. use the standard view of the x, y, and z axes. front half of a cone with a rounded top. full cone with a flat top. right half of a cone with a flat top. front half of a cone with a flat top. right half of a cone with a rounded top.

The table below represents a linear function f(x) and the equation represents a function g(x): x f(x) −1 −5 0 −1 1 3 g(x) g(x) = 2x − 7 part a: write a sentence to compare the slope of the two functions and show the steps you used to determine the slope of f(x) and g(x). (6 points) part b: which function has a greater y-intercept? justify your answer. (4 points)

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