Essica and her sister, Nicole, need money for lunch. Jessica receives $50 and buys lunches at the high school for $2.50 each and Nicole receives $40 and buy lunches at the elementary school for $1.50 each. How many lunches do they have to buy for the two girls to have the same amount of money in their account? $50 - $1.50x = $40 - $2.50x
$50 - $1.50x = $40 - $2.50x

$50 - $2.50x = $40 - $1.50x
$50 - $2.50x = $40 - $1.50x

$50 + $1.50x = $40 + $2.50x
$50 + $1.50x = $40 + $2.50x

$50 + $2.50x = $40 + $1.50x

$50 - $2.50x = $40 - $1.50x

Step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25