At a particular sea level location at a particular time the atmospheric pressure is 14.8 lbs/in^2 and the temperature is 80 degrees F. Estimate the temp, pressure , and air density at an altitude of 8,000ft? 18,000 ft? Note: You must modify the standard atmosphere model using the given values for sea level air pressure and temperature

(a) At 8,000 ft :

The air  temperature is 30.52  °F

The air pressure is 1574 lbs/ft²

The air density is 1.869 x 10⁻³ slug/ft³

(b)  At 18,000 ft :

The air temperature is -5.08  °F

The air pressure is 1059.2 lbs/ft²

The air density is 1.356 x 10⁻³ slug/ft³

Step-by-step explanation:

Given;

pressure at sea level, P₀ = 14.8 PSI

temperature, T' = 80 °F

At 8,000 ft (m) altitude

for altitude h, less than 36,152 ft, the following model is used to modify temperature and pressure;

T = 59 - 0.00356h

T = 59 - 0.00356(8,000)

T = 30.52  °F

The pressure is calculated as;

The density is given by;

For 18,000 ft

T = 59 - 0.00356h

T = 59 - 0.00356(18,000)

T = -5.08 °F

The pressure is calculated as;

The density is given by;

b mark me branliest thx

step-by-step explanation:

step-by-step explanation:

let's assume

number of candles set =x

price of of x candles =p(x)

we are given

a candle maker prices one set of scented candles at $10 and sells an average of 200 sets each week

so, we get point as (200,10)

he finds that when he reduces the price by $1, he then sells 50 more candle sets each week

so, we can find slope

now, we can use point slope form of line

now, we can plug values

we can use point

and find b

now, we can plug it back

and we get

now, we can find revenue

we know that

revenue = price*quantity

so, we get