ANSWER NOW UGH HELP The figure shows the letter T and four of its transformed images—A, B, C, and D:

A letter T is formed on the coordinate plane with endpoints negative 5 comma negative 1, negative 3 comma negative 1, and negative 4 comma negative 3. Figure A has endpoints negative 5 comma 3, negative 3 comma 3, and negative 4 comma 1. Figure B has endpoints negative 1 comma 2, negative 3 comma 2, and negative 2 comma 4. Figure C has endpoints 3 comma negative 1, 4 comma negative 3, and 5 comma negative 1. Figure D has endpoints 2 comma 1, 3 comma 3, and 4 comma 1.

Which of the four images was formed by a reflection of the letter T?

A

B

C

D

the answer is c

Step-by-step explanation:

i just took the test

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.