Lisa is sitting on the dock beside the lake she drops a rock from her hand into the lake after the rock hits the surface of the lake the rocks distance from the lake surface changed at a rate of -3 in./s if Lisa holds her hand 3 feet above the lake surface how hot how far from Lisa's hand is the rock five seconds after hits the surface

4.2495 feets

Step-by-step explanation:

Given the following :

Rate of change (speed) when rock hits the lake surface = - 3in/s

Distance or depth after 5 seconds :

Distance = rate of change * time

Distance = (- 3 in/s × 5) = - 15 inches

1 inch = 0.0833 feet

15 inches = (-15 * 0.0833) = - 1.2495 feets

Distance between Lisa's hand and lake surface = 3 feets :

Distance between Lisa's hand and rock after 5 seconds :

(3 feets + 1.2495 feets) = 4.2495 feets

seems like d

step-by-step explanation: