Three times the smallest of three consecutive of integers is four more than twice the larger. Find the integers.

Step-by-step explanation:

x - the smallest integer

3x  - three times the smallest integer

x+1   - next consecutive integer (the middle)

x+2  - the largest of three consecutive integers

2(x+2) - twice the largest of consecutive integers

2(x+2)+4 - four more than  twice the largest of consecutive integers

3x = 2(x+2)+4

3x = 2x + 4 + 4

-2x    -2x

x = 8

x+1 = 9

x+2 = 10

Or if you mean four more than twice the larger next to the smallest:

x - the smallest integer

3x  - three times the smallest integer

x+1   - next consecutive integer (the middle)

x+2  - the largest of consecutive integers

2(x+1) - twice the consecutive integer larger than the smallest

2(x+1)+4 - four more than twice the consecutive integer larger than the smallest

3x = 2(x+1)+4

3x = 2x + 2 + 4

-2x    -2x

x = 6

x+1 = 7

x+2 = 8

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step-by-step explanation: