Look at each equation. Does the graph of the equation have an end behavior that approaches infinity (∞) as x → −∞? Select Yes or No for A-C.

A). Yes

B). Yes

C). No

Step-by-step explanation:

Option (A). y = -2x - 5

As x → -∞, left end of the line decreases.

As x → ∞, right end of the graph rises.

YES.

Option (B). y = 5(x + 2)³ - 3

As x → -∞ and x → ∞,

Both the ends (left and right) rise upwards.

YES.

Option (C). y = -3ˣ

Since, the given equation is not a polynomial, end behaviors are not defined.

NO.

answer is : muchas/tipicas

have a nice day!

~recklesschicken

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.