In response to the increasing weight of airline passengers, the Federal Aviation Administration in 2003 told airlines to assume that passengers average 196 pounds in the summer, including clothing and carry-on baggage. But passengers vary, and the FAA did not specify a standard deviation. A reasonable standard deviation is 32 pounds. Weights are not Normally distributed, especially when the population includes both men and women, but they are not very non-Normal. A commuter plane carries 18 passengers. What is the approximate probability that the total weight of the passengers exceeds 3928 pounds

0.0016

Step-by-step explanation:

Given the following :

Population mean(m) = 196

Population Standard deviation (sd) = 32

Number of sample (n) = 18

Sample mean (x) = Total weight of sample / number of samples = 3928 / 18 = 218.2

Obtaining the test statistic (z) :

Z = [(x - m) / (sd/√n)]

Z = [(218.2 - 196) / (32/√18)]

Z = [(22.2 / 7.5424723)]

Z = 2.943

Hence,

P(Z > 2.94) = 1 - P(Z < 2.94)

= 1 - 0.9984

= 0.0016

the graph on the bottom right

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral