Suppose that the following frequency table contains data on the number of absences in a school year due to illness or injury for 100 randomly selected high school students. Use the table to determine the median number of absences for these 100 students. Provide your answer with precision to one decimal place. Number of absences 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11

Frequency 25, 10, 10, 5, 9, 12, 9, 9, 4, 2, 3, 2

step-by-step explanation:

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step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

it would be a on edgenuit y

the diagram below is your final answer