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5х – 4у = 90
3х + y = — 56
how do i solve this using elimination?
Answers: 1
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It is given that the quadratic equation hx²-3x+k=0, where h and k are constants, has roots [tex] \beta \: and \: 2 \beta [/tex]express h in terms of k
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5х – 4у = 90
3х + y = — 56
how do i solve this using elimination?...
3х + y = — 56
how do i solve this using elimination?...
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