Container A and container B have leaks. Container A has 800 ml of water and is leaking 6 ml per minute.
Container B has 1000 ml and is leaking 10 ml per minute.
Let m represest the number of minutes the contains are leaking.

How many minutes, m, will it take for the two containers to have the same amount of water? Write and solve an equation to show your work.

The two containers will have the same amount of water in 50 minutes

Step-by-step explanation:

800-6x=1000-10x

hi

step-by-step explanation:

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you