What is the range of the function f(x) = 2x + 3
when the domain is {-3,-1, 1}
a {0,2,4}
b {-3, 1,5
c{3,-1,-5)
d{3,1,5

Choice B

Range = {-3, 1, 5}

Explanation:

The domain is the set of all possible input x values. The range is the set of all possible y outputs.

Plug in each x value from the domain, one at a time, to get its corresponding range y value.

Start with x = -3

f(x) = 2x+3

f(-3) = 2(-3)+3

f(-3) = -6+3

f(-3) = -3

So -3 is in the range.

Move onto x = -1

f(x) = 2x+3

f(-1) = 2(-1)+3

f(-1) = -2+3

f(-1) = 1

1 is also in the range

Finally plug in x = 1

f(x) = 2x+3

f(1) = 2(1)+3

f(1) = 2+3

f(1) = 5

The value 5 is the final value in the range.

All of those values form the set {-3, 1, 5} which is the complete range.

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

idk

step-by-step explanation: