Mathematics, 06.10.2020 22:01, 1031kylepoe03

Conner and Jana are multiplying (3^5 6^8)(3^9 6^10). Conner's Work
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Janas work:

Is either of them correct? Explain your reasoning.

$(3^5 6^8)(3^9 6^{10}) = [tex]3^5 + ^9 6^8 + ^{10}= 3^{14} 6^{18}$
$(3^5 6^8)(3^9 6^{10}) = 3^{5⋅9}6^{8⋅10} = 3^{45}6^{80}$

Answers: 3

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Conner and Jana are multiplying (3^5 6^8)(3^9 6^10). Conner's Work

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