In parallelogram ABCD, DB =28 cm. AN and CM are perpendicular to BD. AN = CM =10 cm. Find the area of the parallelogram.

280 cm

Step-by-step explanation:

The base of each of the congruent triangles ABD and CBD is BD= 28 cm. The height of each is the perpendicular 10cm.

A=(2)(bh/2) works out to A= bh since the 2/2 cancel

So 10cm × 28cm = 280cm²

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°