TIER BANK: C. 24
D. -24
T. 45
U. -45
1)-4 x 8
A. 32
B. -32
2) -3 -3
A. 9
B. -9
3) 7 X-8
1. 56
J.-49
4) - 6 X -3
P.-18
Q. 18
C. 6
D. -6
A G P E 0 LP
IS A REBL
5) 5 x 9
R. -50
S. -40
6) -4 X 7
0.28
P. 21
7)-2 8
P. -16
Q.-14
8) -9-9
D. 72
E. -72
Q.-35
R.-28
K. 49
L. -56
R. 16
S. 14
R. 12
S. -12
F. 81
G. -81
Code:
Math in the Midwest 2019

ind the Laplace transform of the following functions: (a) t cos tu(t) (b) e⁻ᵗ t ... (2t + 4)u(t) (b) g(t) = (4 + 3e⁻²ᵗ)u(t) (c) h(t) = (6 sin(3t) + 8 cos(3t))u(t) (d) x(t) = … ... to solve the given initial value problem.y"+2y'+5y=0;y(0)=2,y'(0)=−1 3 answers.

2 answers

Step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

step-by-step explanation:

the triangles are similar. therefore the corresponding sides are in proportion:

              cross multiply

            divide both sides by 32