Drag a reason to each box to complete the proof. Given: KM=LN segment K N with points K L M N on the segment in order from left to right Prove: KL=MN Statements Reasons KM=LN Response area KM=KL+LM Segment Addition Postulate LN=LM+MN Response area KL+LM=LM+MN Substitution Property of Equality KL=MN look below for options DO IT NO BOT ANSWERS WILL BE TOLLERATED

KM=LNGiven

KM=KL+LMSegment Addition Postulate

LN=LM+MNSegment Addition Postulate

KL+LM=LM+MNSubstitution Property of Equality

KL=MNSubstitution Property of Equality

hope this helped :)

KM=LN  Given

KM=KL+LM  Segment Addition Postulate

LN=LM+MN  Segment Addition Postulate

KL+LM=LM+MN  Substitution Property of Equality

KL=MN  Subtraction Property of Equality

Step-by-step explanation:

Verified correct with test results.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

d

step-by-step explanation: