1. Curtis was curious about the average height of the different types of plants in his flower and vegetable gardens, so he measured each of his plants. This data set shows the heights of the flowers in his garden, in inches. This data set shows the heights of the vegetable plants in his garden, in inches:
(a) What is the mean absolute deviation (MAD) of the flower height data? Show your work.
(b) What is the mean absolute deviation (MAD) of the vegetable height data? Show your work.
(c) Use the data to compare the two gardens. What does the MAD indicate about the variability between flower and vegetable plant heights

Step-by-step explanation:

For part a, take all the data ( in your case line up the flower's height in inches) and find the mean. To do this you add all of the numbers together and divide by the number of numbers (EXA: 13,4,12,7---> 13+4+12+7= 36---> 36/4=9; 9 is the mean)

For part b, do the same thing, except use the values for the vegitable heights.

For part c, it's asking you to compare the values, (find their differences) and figure out the variability, which means to find the pattern in growth between both the flowers and vegitables, and explian them.

I hope this helps! :)

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)