Mathematics, 04.10.2020 08:01, hannaboo53
What is wrong with the equation? 2 x−3 dx = x−2 −2 2 −3 = − 5 72 −3 f(x) = x−3 is continuous on the interval [−3, 2] so FTC2 cannot be applied. f(x) = x−3 is not continuous at x = −3, so FTC2 cannot be applied. f(x) = x−3 is not continuous on the interval [−3, 2] so FTC2 cannot be applied. There is nothing wrong with the equation. The lower limit is less than 0, so FTC2 cannot be applied.
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