A recent survey was conducted to compare the cost of solar energy to the cost of gas or electric energy. Results of the survey revealed that the distribution of the amount of the monthly utility bill of a 3-bedroom house using gas or electric energy had a mean of $97 and a standard deviation of $10. If the distribution can be considered mound-shaped and symmetric, what percentage of homes will have a monthly utility bill of more than $87

The percentage  of homes will have a monthly utility bill of more than $87

P(X>87) = 0.8413 X 100 = 84.13%

Step-by-step explanation:

Explanation:-

Given Mean of the Population =97

Standard deviation of the Population = 10

Let 'X' be the random variable in normal distribution

      Z= -1

The probability that  homes will have a monthly utility bill of more than $87

P(X>87) = P( Z>-1) = 0.5 + A(-1)

                            = 0.5 + A(1)     (∵A(-1)=A(1)

                           =0.5 +  0.3413

                           = 0.8413

The percentage  of homes will have a monthly utility bill of more than $87

P(X>87) = 0.8413 X 100 = 84.13%

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

i think the answer is fried chicken ; >

step-by-step explanation: