20 years ago the age of father was 5 times the age of his son. at peesent father's age is 10 years more than twice his sons. find theur present ages URGENT FAST HELP PLEASE

Step-by-step explanation:

At present:

Let son's age = x

Father's age = 2x + 10

Before 20 years:

son's age = x - 20

Father's age = 2x + 10 - 20 = 2x - 10

Father's age = 5 * (Son's age)

         2x - 10 = 5*(x - 20)

        2x - 10 = 5x - 100 {add 100 to both sides}

2x -10 + 100 = 5x - 100 +100

     2x  + 90 = 5x            {Subtract  2x from both sides}

2x + 90 - 2x = 5x- 2x

             90  = 3x               {divide both sides by 3}

          90/3 = x

x = 30

Present age of :

Son = 30 years

Father = 2*30 +10 = 60 + 10

           = 70 years

well first make sure that you are black. then rob a gas station and the kill the attendant

step-by-step explanation:

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500