Use the given conditions to write an equation for the line in point-slope form and general form. Passing through (-4,8) and parallel to the line whose equation is 3x-8y-7=0

Step-by-step explanation:

Hey there!

The equation of a st.line passing through point is;

(y - 8) = m1(x+4).........(i).

And another equation is;

3x - 8y - 7 =0.......(ii)

From equation (ii), we get;

Therefore the slope is 3/8.

As they are parallel lines, their slopes are eaual.

i.e m1 = m2 = 3/8.

Putting value of slope (m1) in equation (i).

Simplify them to get equation.

Therefore therequired equation is 3x - 8y +76=0.

Hope it helps...