(y − 3)^2 = 4(x − 5), (6, 1). Find an equation of the tangent line to the graph at the given point.

y=x−1. Explanation: (y−3)2=4(x −5). Expanding: y2−6y+9=4x−20. y2−6y−4x=− 29. Differentiating implicitly: 2ydydx−6dydx−4=0.

y=x−1 Explanation: (y−3)2=4(x−5) Expanding: y2−6y+9=4x−20 y2−6y−4x=−29 Differentiating implicitly: 2ydydx−6dydx−4=0 Factor: ... More

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.