Find the equation of the line in slope intercept form parallel to 5x−5y=−2 and goes through the point (−10,4) y=?

y = x + 14

Step-by-step explanation:

given

5x−5y=−2, we'll rearrange this into slope - intercept form

5x + 2 = 5y

5y = 5x + 2    (divide both sides by 5)

y = x + (2/5)

recall that the general equation of the slope-intercept form of a linear equation:

y = mx + b, the value of m represents the slope of the line

in our case, comparing the above equations, it is clear that the slope m = 1.

We are given that our line is parallel to the above line, hence it will also have  a slope of 1.

if we substitute m = 1 into the general equation, we will get

y = x + b

in order to find the value of b, we will substitute the given point (-10,4) into the equation:

4 = -10 + b   (add 10 to both sides)

b = 4 + 10

b = 14

hence our equation is y = x + 14

answer: i'm great at algebra

~coco

step-by-step explanation: