1. Kyle has a baseball game after school. He drives 6 miles due west from his home to school. After school, he drives 5 miles due north to the baseball field, as shown on the grid below What is the straight-line distance from the baseball field to Kyles home, to the nearest tenth of a mile? A. 3.3 miles B. 5.5 miles C. 7.4 miles D. 7.8 miles

D. 7.8 miles.

Step-by-step explanation:

So, to solve this, you need to use the Pythagorean theorem to find the distance from the baseball field to his home. You know two of the sides of the triangle formed, 6 and 5. The Pythagorean theorem is a² + b² = c². In this case, it would be 6² + 5² = c². If you solve this, you would find that c is 7.81024967591. Just round it to the nearest tenth like instructed. This would get you 7.8 as the answer.

Extra work just in case:

6² + 5² = c²

36 + 25 = c²

61 = c²

=

7.8 ≈ c

Visual just in case:

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!