Gold has a density of 0.70 pounds per cubic inch and copper has a density of 8.96 grams per cubic centimeter. How much will 1 cubic foot of each metal weigh? 1 ft(3) = 1728 in(3), 1 ft(3) = 28,316.8 cm cubed, and 1 lb = 453.5 g.
"use the equation p=m/v

1 cubic foot of gold will weigh 1209.6 pounds

1 cubic foot of copper will weigh 559 pounds.

Step-by-step explanation:

Density = Mass/Volume

Mass = Density × Volume

Volume of each metal = 1 ft³

a) Gold

Density of Gold = 0.70 pounds per cubic inch(lb/in³)

We will be converting the Volume of gold from cubic foot to cubic inches

The Volume of gold given in the question = 1 cubic foot = 1 ft³

1 cubic foot = 1728 cubic inches

Hence, the volume of Gold = 1728 in³

Mass of Gold = Density of Gold × Volume of Gold

Mass of Gold = 0.70Ib/in³ × 1728 in³

= 1209.6 lb(pounds)

2) Copper

Density of copper = 8.96 grams per cubic centimeter

Ib = pounds

We convert this density in g/cm³ to ib/in³

453.5g = 1 Ib

8.96g = y Ib

Cross Multiply

= 453.5g × y Ib =8.96g × 1 Ib

= y Ib = 8.96g × 1 Ib/453.5g

y Ib = 0.0197574421 Ib

Density of Copper = 0.0197574421 Ib/cm³

28,316.8 cm³ = 1 ft³

1 cm³ = x ft³

x ft³ = 1 cm³ × 1 ft³/28,316.8cm³

x ft³ = 0.0000353147 ft³

1 cm³ = 0.0000353147 ft³

We have to convert the density of Copper from Ib/cm³ to Ib/ft³

0.0197574421 Ib/cm³ = 0.0197574421 Ib/0.0000353147 ft³

559.46793026 Ib/ft³

Volume of copper = 1ft³

Mass = Density × Volume

Mass of copper = 559.46793026 Ib/ft³ × 1 ft³

= 559.46793026 Ib or pounds

≈ 559 pounds

Therefore , the weight of gold is 1209.6 pounds and the weight of copper will be 559 pounds.

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value