In physics, kinetic energy is the energy of an object in motion. Kinetic energy, KKK, measured in joules (\text{J})(J)left parenthesis, start text, J, end text, right parenthesis, is calculated using the formula K =\dfrac{1}{2}mv^2K= 2
1

mv
2
K, equals, start fraction, 1, divided by, 2, end fraction, m, v, squared, where mmm is the mass of the object, measured in kilograms (\text{kg})(kg)left parenthesis, start text, k, g, end text, right parenthesis, and vvv is the velocity of the object, measured in meters per second (\text{m}/\text{s})(m/s)left parenthesis, start text, m, end text, slash, start text, s, end text, right parenthesis.
sorry for this khan academy acting dumb

what?

step-by-step explanation:

what do you need with. i love quadrants. can you tell me ?

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.