Drag numbers into the blanks to show that f(x) = x - 2x + 5 has exactly 2 roots in the set of complex numbers by completing the square. x² - 2x+5=0
2-2x =
x² - 2x+
(x - 1)2 =
(x - 1) = +
Therefore, there are two roots of f(x), x =
and x =
-5
-4
-3
-2
- 1
0
1
2
3
4
5
21
1 + 2
1 -2i
-1 + 2i
-1-2i