Arobot is at position A(30,40) and is heading toward the point B (1000, 1000) along a straight line at a constant speed. The robot will reach point B in 10 hours.

What is the location of the robot at the end of the fourth hour?

(418, 424)

Step-by-step explanation:

Arobot travels at constant speed. The total trip takes 10 hours. We want to know its position is 4 hours. The fraction of the path it will travel in 4 hours is 4/10 of the entire path. We need to find what point is 4/10 of the way from point A to point B.

For each coordinate, we find 4/10 of the difference between point A and B, and we add it tot eh coordinate of point A.

x-coordinate:

difference in x-coordinates: 1000 - 30 = 970

4/10 * 970 = 388

30 + 388 = 418

The x-coordinate is 418

y-coordinate:

difference in x-coordinates: 1000 - 40 = 960

4/10 * 960 = 384

40 + 384 = 424

The x-coordinate is 424

(418, 424)

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.