Solve the equation -2y+4=8y-6

Move all terms containing

y to the left side of the equation.Subtract 8y from both sides of the equation.

−2y+4−8y=−6

Subtract

8y from −2y

-10y+4=−6

Move all terms not containing y to the right side of the equation.

Subtract 4 from both sides of the equation

−10y=−6−4

Subtract 4 from −6.

−10y=−10

Divide each term by −10 and simplify.

y=1

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

maybe - definition of supplementary angles. im not sure. sorry

step-by-step explanation: