Solve: 6(t-3) = 2(9 - 2t)
T=

6(t-3)=2(9-2t)=

We move all terms to the left:

6(t-3)-(2(9-2t))=0

We add all the numbers together, and all the variables

6(t-3)-(2(-2t+9))=0

We multiply parentheses

6t-(2(-2t+9))-18=0

We calculate terms in parentheses: -(2(-2t+9)), so:

2(-2t+9)

We multiply parentheses

-4t+18

Back to the equation:

-(-4t+18)

We get rid of parentheses

6t+4t-18-18=0

We add all the numbers together, and all the variables

10t-36=0

We move all terms containing t to the left, all other terms to the right

10t=36

t=36/10

i belive the biggest ratio would be 18: correct me if im wrong