Paul says that in the number 6367 one 6 is 10 times as great as the other 6. is correct ? explain why or why not.

No.

Step-by-step explanation:

The given number = 6367

Here, the place value of the first 6= 6000 or 6 thousandth.

Also, the place value of the second 6 = 60 or 9=6 tens.

The number of times 6000 is greater than 60 :-

Hence, the place value of first 6 is 100 times graeter tahn the palce value of second 6.

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.