Triangle ABC is reflected over the line y = x to produce triangle A'B'C'. What will be the coordinates of A'? A (2,−1) B (−2,−1) C (2,1) D (1,2)

when P(x,y) is reflected in y=x line then

P(x,y) = P(y,x)

A(2, -1)= A(-1, 2)

B(-2, -1) = B(-1, -2)

C(2, 1)= C(1, 2)

D(1,2)= D(2,1)

Step-by-step explanation:

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!