(8r2 -12r +4) - (3r2 + 5r -1)

Answer  5r^ 2 −17r+5

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "r2"   was replaced by   "r^2".  1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

 (((8•(r2))-12r)+4)-((3r2+5r)-1)

STEP  

2

:

Equation at the end of step

2

:

 ((23r2 -  12r) +  4) -  (3r2 + 5r - 1)

STEP

3

:

Trying to factor by splitting the middle term

3.1     Factoring  5r2-17r+5  

The first term is,  5r2  its coefficient is  5 .

The middle term is,  -17r  its coefficient is  -17 .

The last term, "the constant", is  +5  

Step-1 : Multiply the coefficient of the first term by the constant   5 • 5 = 25  

Step-2 : Find two factors of  25  whose sum equals the coefficient of the middle term, which is   -17 .

     -25    +    -1    =    -26  

     -5    +    -5    =    -10  

     -1    +    -25    =    -26  

     1    +    25    =    26  

     5    +    5    =    10  

     25    +    1    =    26  

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

 5r^2 - 17r + 5

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~