KD bisects angle JKL and m angle DKL=23.6 Find m JKD and m JKL

m∠JKD = 23.6°

m∠JKL = 47.2°

Step-by-step explanation:

Since KD is the angle bisector of angle JKL.

Therefore, m∠JKD = m∠DKL

Measure of angle DKL = 23.6°

Therefore, m∠JKD = m∠DKL = 23.6°

Since, ∠JKL = 2(m∠JKD) [Given that DK is the angle bisector of angle JKL]

                    =  2(23.6)°

                    = 47.2°

perimeter = 10 +  √10  units

explanation:

first, we will need to get the length of each line using the distance formula which is as follows:

distance = 

1- length of ab:

ab =   = 5 units

2- length of ac

length of ac is the same as ab = 5 units

3- length of bc:

bc =   =  √10  units

now, we can get the perimeter by adding the side lengths as follows:

perimeter = 5 + 5 +  √10

perimeter = 10 +  √10  units

hope this : )

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