AUL ball 1/10 of the length of the field and mark hit the ball 3/8 of the length of the field. Together, what fraction of the length of the field did they hit the ball.

19/40

Step-by-step explanation:

AUL ball hit 1/10 of the length of the field

Mark ball hit 3/8 of the field.

Therefore the fraction of the length of the field in which they hit the ball can be calculated as follows

= 1/10 + 3/8

= 38/80

= 19/40

Hence the fraction of the length of the field in which they hit the ball together is 19/40

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c