A certain company has two car assembly plants, A and B. Plant A produces twiceas many cars as plant B. Plant A uses engines and transmissions from a subsidiaryplant which produces 10% defective engines and 2% defectivetransmissions. Plant B uses engines and transmissions from another source where8% of the engines and 4% of the transmissions are defective. Car transmissionsand engines at each plant are installed independently. a) What is the probability that a car chosen at random will have a good engine?
b) What is the probability that a car from plant A has a defective engine, or adefective transmission, or both?
c) What is the probability that a car which has a good transmission and adefective engine was assembled at plant B?

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

step-by-step explanation:

135

step-by-step explanation:

blah f

df

vdf

vd

fvdf

(−$11) ⋅ 12

deductions are subtracted and there are 12 months in a year