What interval includes all possible values of x, where -3(6 - 2x) >4x + 12 O (-00, -3]
OF-3,00)
0 (0o, 15]
O [15,00)

Step-by-step explanation:

-3(6 - 2x) > 4x + 12

-18 + 6x > 4x + 12

2x > 30

x > 15

The solution set is (15, ∞).

answer: slight chance that it will happen

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: