Mathematics, 22.09.2020 08:01, missbecca1229p6glel
Solve for x: 2x^5/3-22=464 a) x = 28 b) x = 27 c) x = ±27 d) x = ±28
Answers: 1
, we are to find the value of x in the expression. This is as shown below;
![(x^{5/3})^{3/5} = (243)^{3/5}\\x = (\sqrt[5]{243}) ^3\\x = 3^3\\x = 27](/tpl/images/0775/7461/41559.png)
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Solve for x: 2x^5/3-22=464 a) x = 28 b) x = 27 c) x = ±27 d) x = ±28...
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